The determinant in 'n' dimentions is the exterior product of 'n' vectors, this gives the multipier of the pseudoscalar. For instance:
- In 2 dimensions the determinant of 2 vectors is A /\ B which has units of e12
- In 3 dimensions the determinant of 3 vectors is A /\ B /\ C which has units of e123
- In 'n' dimensions the determinant of n vectors is A1 /\ ... An which has units of e1...n
The geometric interpretation of this is shown on this page.
To illustrate this we will start with 2 dimensions:
Two dimensions
Imagine we want to find the directed area enclosed by the parallelogram between two vectors in a plane then we can take the '/\' product:
For example if the two vectors are:
2 e1 + 5 e2
3 e1 + 4 e2
then the directected area is the bivector part of:
(2 e1 + 5 e2) /\ (3 e1 + 4 e2)
Assuming we are working in euclidean space, that is e1 and e2 both square to +1, then we get:
2 e1 /\ 3 e1 + 5 e2 /\ 3 e1+ 2 e1 /\ 4 e2 + 5 e2 /\ 4 e2
but the exterior product of common terms is zero: e1 /\ e1= e2 /\ e2 = 0 so the result is:
(2*4 - 5*3) e12
So the bivector part is 2*4 - 5*3, in matrix notation this is:
|
e12 |
In the more general case, if we have two vectors (Ax,Ay) and (Bx,By) then the directed area will be (in matrix notation):
|
= A /\ B |
Note: we can put the e1 and e2 operators inside this notation:
which expands to give: (Ax e1)(By e2) - (Ay e1)(Bx e2) = (Ax*By - Ay*Bx)e12 Order is important here so the determinant is defined as top-left* bottom-right - bottom-left *top-right |
Can this be generalised to 'n' dimensions?
|
= Ax |
|
- Ay |
|
+ Az |
|
and recursing down to the next level gives:
|M| = Ax By Cz + Ay Bz Cx + Az Bx Cy - Ax Bz Cy - Ay Bx Cz - Az By Cx
A /\ B /\ C = (Ax e1 + Ay e2+ Az e3) /\ (Bx e1 + By e2+ Bz e3) /\ (Cx e1 + Cy e2+ Cz e3)
= (Ax*By e12+ Ax*Bz e13
- Ay*Bx e12 + Ay*Bz e23
+ Az*Bx e31 - Az*By e23) /\ (Cx e1 + Cy e2+ Cz e3)
= ((Ax*By- Ay*Bx) e12+ (Az*Bx-Ax*Bz) e31
+ (Ay*Bz - Az*By) e23)) /\ (Cx e1 + Cy e2+ Cz e3)
= (Ax*By- Ay*Bx)e12 (Cx e1 + Cy e2+ Cz e3)
+ (Az*Bx-Ax*Bz)e31 (Cx e1 + Cy e2+ Cz e3)
+ (Ay*Bz - Az*By) e23)(Cx e1 + Cy e2+ Cz e3)
= (Ax*By- Ay*Bx)Cz e123 + (Az*Bx-Ax*Bz)Cy e312 + (Ay*Bz - Az*By)Cx e231
so the resulting pseudoscalar term is:
Ax*By*Cz- Ay*Bx*Cz + Az*Bx*Cy-Ax*Bz*Cy+ Ay*Bz*Cx - Az*By*Cx
which has the same form as |M| above with a few sign changes, I must have reversed the order somewhere.